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Q.
Two energy levels of an electron in an atom are separated by $ 2.3 \,eV $ . The frequency of radiation emitted when the electrons to go from higher to lower level is
AMUAMU 2010Atoms
Solution:
Given, $E_{2}-E_{1}=2.3\,eV$
or $V=\frac{E_{2}-E_{1}}{h}$
$=\frac{2.3\times1.6\times10^{-19}}{6.6\times 10^{-34}}$
$=0.55\times10^{15}$
$=5.5\times 10^{14}\,HZ$