Two elements 'P' and 'Q' combine to form a compound. Atomic mass of 'P' is 12 and 'Q' is 16. Percentage of 'P' in the compound is 27.3. What will be the empirical formula of the compound?

Question

Two elements 'P' and 'Q' combine to form a compound. Atomic mass of 'P' is 12 and 'Q' is 16. Percentage of 'P' in the compound is 27.3. What will be the empirical formula of the compound? (A) P2Q2 (B) PQ (C) P2Q (D) PQ2

Tardigrade Admin · Accepted Answer

Element % No. of Moles Mole ratio Whole no. ratio P 27.3 27.3/12=2.27 1 1 Q 72.7 72.7/16=4.54 2 2 Empirical Formula = PQ2

Q. Two elements $^{'} P^{'}$ and $^{'} Q^{'}$ combine to form a compound. Atomic mass of $^{'} P^{'}$ is $12$ and $^{'} Q^{'}$ is $16$ . Percentage of $^{'} P^{'}$ in the compound is $27.3$ . What will be the empirical formula of the compound?

$P_{2} Q_{2}$

$PQ$

$P_{2} Q$

$P Q_{2}$

Element % No. of Moles Mole ratio Whole no. ratio

P 27.3 27.3/12=2.27 1 1

Q 72.7 72.7/16=4.54 2 2

Empirical Formula $= P Q_{2}$

Q. Two elements ′P′ and ′Q′ combine to form a compound. Atomic mass of ′P′ is 12 and ′Q′ is 16. Percentage of ′P′ in the compound is 27.3. What will be the empirical formula of the compound?

P2​Q2​

PQ

P2​Q

PQ2​