Q. Two elements $'P'$ and $'Q'$ combine to form a compound. Atomic mass of $'P'$ is $12$ and $'Q'$ is $16$. Percentage of $'P'$ in the compound is $27.3$. What will be the empirical formula of the compound?
Some Basic Concepts of Chemistry
Solution:
Element
%
No. of Moles
Mole ratio
Whole no. ratio
P
27.3
27.3/12=2.27
1
1
Q
72.7
72.7/16=4.54
2
2
Empirical Formula $= PQ_{2}$
Element | % | No. of Moles | Mole ratio | Whole no. ratio |
---|---|---|---|---|
P | 27.3 | 27.3/12=2.27 | 1 | 1 |
Q | 72.7 | 72.7/16=4.54 | 2 | 2 |