Two electrolytic cells, one containing acidified ferrous chloride and another acidified ferric are connected in series. The ratio of iron deposited at cathodes in the two cells will be

Question

Two electrolytic cells, one containing acidified ferrous chloride and another acidified ferric are connected in series. The ratio of iron deposited at cathodes in the two cells will be (A) 3: 1 (B) 2: 1 (C) 1:1 (D) 3: 2

Tardigrade Admin · Accepted Answer

Since the wt. of iron deposited is proportional to its equivalent weight ∴ ( textWt. of ferrous ion/ textWt. of ferric iron ) = ( text at. wt/2/ text at wt. /3) = 3/2

Q. Two electrolytic cells, one containing acidified ferrous chloride and another acidified ferric are connected in series. The ratio of iron deposited at cathodes in the two cells will be

3 : 1

2 : 1

1:1

3 : 2

Since the wt. of iron deposited is proportional to its equivalent weight
$∴ \frac{Wt. of ferrous ion}{Wt. of ferric iron}$
$= \frac{at. wt/2}{at wt. /3} = 3/2$

Q. Two electrolytic cells, one containing acidified ferrous chloride and another acidified ferric are connected in series. The ratio of iron deposited at cathodes in the two cells will be

3 : 1

2 : 1

1:1

3 : 2

Since the wt. of iron deposited is proportional to its equivalent weight ∴Wt. of ferric ironWt. of ferrous ion​ =at wt. /3at. wt/2​=3/2

Since the wt. of iron deposited is proportional to its equivalent weight
$∴ \frac{Wt. of ferrous ion}{Wt. of ferric iron}$
$= \frac{at. wt/2}{at wt. /3} = 3/2$