Two electric dipoles of dipole moments 1.2 × 10-30 cm and 2.4 × 10-30 cm are placed in two difference uniform electric fields of strengths 5 × 104 NC -1 and 15 × 104 NC -1 respectively. The ratio of maximum torque experienced by the electric dipoles will be (1/ x ). The value of x is

Question

Two electric dipoles of dipole moments 1.2 × 10-30 cm and 2.4 × 10-30 cm are placed in two difference uniform electric fields of strengths 5 × 104 NC -1 and 15 × 104 NC -1 respectively. The ratio of maximum torque experienced by the electric dipoles will be (1/ x ). The value of x is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

|τ| max = PE (τ1/τ2)=( P 1 E 1/ P 2 E 2)=(1.2 × 10-30 × 5 × 104/2 ⋅ 4 × 10-30 × 15 × 104)=(1/6) Hence x=6

Q. Two electric dipoles of dipole moments 1.2×10−30cm and 2.4×10−30cm are placed in two difference uniform electric fields of strengths 5×104NC−1 and 15×104NC−1 respectively. The ratio of maximum torque experienced by the electric dipoles will be x1​. The value of x is ____

∣τ∣max​=PE τ2​τ1​​=P2​E2​P1​E1​​=2⋅4×10−30×15×1041.2×10−30×5×104​=61​ Hence x=6

$∣ τ ∣_{m a x} = PE$
$\frac{τ _{1}}{τ _{2}} = \frac{P _{1} E _{1}}{P _{2} E _{2}} = \frac{1.2 \times 1 0 ^{- 30} \times 5 \times 1 0 ^{4}}{2 \cdot 4 \times 1 0 ^{- 30} \times 15 \times 1 0 ^{4}} = \frac{1}{6}$
Hence $x = 6$