Two different coils of self inductance L1 and L2 are placed close to each other so that the effective flux in one coil is completely linked with other. If M is the mutual inductance between them, then

Question

Two different coils of self inductance L1 and L2 are placed close to each other so that the effective flux in one coil is completely linked with other. If M is the mutual inductance between them, then (A)  M = L1/L2  (B)  M = L1L2  (C)  M=√L1L2  (D)  M=(L1 L2)2

Tardigrade Admin · Accepted Answer

We know that, M=-(e2/d i1 / d t)=-(e1/d i2 / d t) Also, e1=-L1 (d i1/d t) and e2=-L2 (d i2/d t) ⇒ M2=(e1 e2/((d i1)dt)((di2)d t)=L/1) L2 ⇒ M=√L1 L2

Q. Two different coils of self inductance $L_{1}$ and $L_{2}$ are placed close to each other so that the effective flux in one coil is completely linked with other. If $M$ is the mutual inductance between them, then

$M = L_{1} / L_{2}$

$M = L_{1} L_{2}$

$M = L_{1} L_{2}$

$M = (L_{1} L_{2})^{2}$

Q. Two different coils of self inductance L1​ and L2​ are placed close to each other so that the effective flux in one coil is completely linked with other. If M is the mutual inductance between them, then

M=L1​/L2​

M=L1​L2​

M=L1​L2​​

M=(L1​L2​)2

We know that, M=−di1​/dte2​​=−di2​/dte1​​ Also, e1​=−L1​dtdi1​​ and e2​=−L2​dtdi2​​ ⇒M2=(dtdi1​​)(dtdi2​​)e1​e2​​=L1​L2​ ⇒M=L1​L2​​

Q. Two different coils of self inductance $L_{1}$ and $L_{2}$ are placed close to each other so that the effective flux in one coil is completely linked with other. If $M$ is the mutual inductance between them, then

$M = L_{1} / L_{2}$

$M = L_{1} L_{2}$

$M = L_{1} L_{2}$

$M = (L_{1} L_{2})^{2}$