Two dice are thrown together, then the probability that sum of these two number is a prime number if it is given that both the results are prime numbers

Question

Two dice are thrown together, then the probability that sum of these two number is a prime number if it is given that both the results are prime numbers (A) (4/9) (B) (1/4) (C) (2/3) (D) (5/9)

Tardigrade Admin · Accepted Answer

S= (2,2),(2,3)(2,5),(3,2)(3,3)(3,5),(5,2)(5,3),(5,5) Probability, =4 / 9

Q. Two dice are thrown together, then the probability that sum of these two number is a prime number if it is given that both the results are prime numbers

$\frac{4}{9}$

$\frac{1}{4}$

$\frac{2}{3}$

$\frac{5}{9}$

$S = {(2, 2), (2, 3) (2, 5), (3, 2) (3, 3) (3, 5), (5, 2) (5, 3), (5, 5)}$
Probability, $= 4/9$