Two dice are thrown together . If both numbers appearing are different, then what is the probability that their sum is 5 ?

Question

Two dice are thrown together . If both numbers appearing are different, then what is the probability that their sum is 5 ? (A) (1/6) (B) (1/9) (C) (1/12) (D) (1/5)

Tardigrade Admin · Accepted Answer

Favourable outcomes: (1,4),(2,3),(3,2),(4,1) P( sum =5)=(4/6 × 5)=(2/15)

Q. Two dice are thrown together . If both numbers appearing are different, then what is the probability that their sum is 5 ?

$\frac{1}{6}$

$\frac{1}{9}$

$\frac{1}{12}$

$\frac{1}{5}$

$\frac{2}{15}$

Favourable outcomes : $(1, 4), (2, 3), (3, 2), (4, 1)$
$P ($ sum $= 5) = \frac{4}{6 \times 5} = \frac{2}{15}$