Two dice are thrown. If it is known that the sum of numbers on the dice was less than 6 the probability of getting a sum as 3 is

Question

Two dice are thrown. If it is known that the sum of numbers on the dice was less than 6 the probability of getting a sum as 3 is (A) (1/18)  (B) (5/18) (C) (1/5) (D) (2/5)

Tardigrade Admin · Accepted Answer

(1,1)(1,2)(1,3)(1,4)(2,1)(2,2)(2,3) (3,1)(3,2)(4,1) P(B)=(10/36) n ( A )=(1,2)(2,1) P ( A )=(2/36) P (( B / A ))=((2/36)/(10)36) =(2/10)=(1/5)

Q. Two dice are thrown. If it is known that the sum of numbers on the dice was less than $6$ the probability of getting a sum as $3$ is

$\frac{1}{18}$

$\frac{5}{18}$

$\frac{1}{5}$

$\frac{2}{5}$

$(1, 1) (1, 2) (1, 3) (1, 4) (2, 1) (2, 2) (2, 3)$
$(3, 1) (3, 2) (4, 1)$
$P (B) = \frac{10}{36}$
$n (A) = (1, 2) (2, 1)$
$P (A) = \frac{2}{36}$
$P (\frac{B}{A}) = \frac{\frac{2}{36}}{\frac{10}{36}}$
$= \frac{2}{10} = \frac{1}{5}$

Q. Two dice are thrown. If it is known that the sum of numbers on the dice was less than 6 the probability of getting a sum as 3 is

181​

185​

51​

52​