Question

Two dice are thrown and two coins are tossed simultaneously. The probability of getting prime numbers on both the dice along with a head and a tail on the two coins is

• A. $\frac{1}{8}$
• B. $\frac{1}{2}$
• C. $\frac{3}{16}$
• D. $\frac{1}{4}$

Answer 1

Answer: (A)

Since number of getting prime numbers $\{2,3,5\}$ is 3 therefore number of getting prime numbers on both the dice is $3\times 3$.
And getting a head and a tail on two coins $=1\times 1\times 2$
And total number of possibilities $=(6\times 6)\times (2\times 2)$
So, required probability $=\frac{3\times 3\times 1\times 1\times 2}{16\times 6\times 2\times 2}=\frac{1}{8}$