Q.
Two conducting spheres of radii 5cm and 10cm are given a charge of 15μC each. After connecting the spheres by a copper wire, the charge on the smaller sphere is equal to
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Electrostatic Potential and Capacitance
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Solution:
Common potential, V=C1+C2Q1+Q2 V=4πε0r1+4πε0r2Q1+Q2=4πε0(r1+r2)Q1+Q2 =4πε0(5+10)×10−230μC =15×10−230×10−6×9×109=18×105V
Charge on smaller sphere, Q1′=4πε0r1V =9×1091×5×10−2×18×105 =10×10−6C=10μC