Two conducting spheres each of radius R carry charge q. They are placed at a distance r from each other, where r 2 R. The neutral point lies at a distance r/2 from either sphere. If the electric field at the neutral point due to either sphere be E, then the total electric potential at that point will be:

Question

Two conducting spheres each of radius R carry charge q. They are placed at a distance r from each other, where r > 2 R. The neutral point lies at a distance r/2 from either sphere. If the electric field at the neutral point due to either sphere be E, then the total electric potential at that point will be: (A) r E/2 (B) rE (C) RE/2 (D) RE

Tardigrade Admin · Accepted Answer

E = (1/4 π ε0) (q/(r/2)2) , V = 2 [ (1/4 π ε0) (q/(r/2)) ] Therefore (V/E) = r . Hence V = rE.

r E/2

rE

RE/2

RE

E=4πε0​1​(r/2)2q​,V=2[4πε0​1​(r/2)q​] Therefore EV​=r . Hence V=rE.

$E = \frac{1}{4 π ε _{0}} \frac{q}{( r /2 ) ^{2}}, V = 2 [\frac{1}{4 π ε _{0}} \frac{q}{( r /2 )}]$ Therefore $\frac{V}{E} = r$ . Hence $V = r E .$