Q.
Two conducting spheres A and B of radius a and b respectively are at the same potential. The ratio of the surface charge densities of A and B is
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KEAMKEAM 2009Electrostatic Potential and Capacitance
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Solution:
Given electric potential of spheres are same ie, VA=VB4πε01.aQ1=4πε01.bQ2 Q2Q1=ba ..(i)
Surface charge density σ=4πr2Q ⇒σ2σ1=Q2Q1×a2b2 =ba×a2b2=ab