Two concentric spherical conducting shells of radii R and 2R carry charges Q and 2Q respectively. Change in electric potential on the outer shell when both are connected by a conducting wire is ( textk = (1/4 (π Îµ)0))

Question

Two concentric spherical conducting shells of radii R and 2R carry charges Q and 2Q respectively. Change in electric potential on the outer shell when both are connected by a conducting wire is ( textk = (1/4 (π Îµ)0)) (A) zero (B) (3 textkQ/2 textR) (C) ( textkQ/ textR) (D) (2 textkQ/ textR)

Tardigrade Admin · Accepted Answer

When two concentric shells are connected by a wire the whole charge on inner shell is transferred to the outer shell.
Potential of the outer shell

(V)_{i} = \frac{kQ}{2 R} + \frac{k ( 2 Q )}{2 R}

V_{i} = \frac{3 kQ}{2 R}

(V)_{f} = \frac{k ( 3 Q )}{2 R}

∴ Δ V = V_{f} - V_{i} = 0

Q. Two concentric spherical conducting shells of radii $R$ and $2 R$ carry charges $Q$ and $2 Q$ respectively. Change in electric potential on the outer shell when both are connected by a conducting wire is $(k = \frac{1}{4 ( π ε ) _{0}})$

zero

$\frac{3 kQ}{2 R}$

$\frac{kQ}{R}$

$\frac{2 kQ}{R}$

When two concentric shells are connected by a wire the whole charge on inner shell is transferred to the outer shell.
Potential of the outer shell
$(V)_{i} = \frac{kQ}{2 R} + \frac{k ( 2 Q )}{2 R}$
$V_{i} = \frac{3 kQ}{2 R}$
$(V)_{f} = \frac{k ( 3 Q )}{2 R}$
$∴ Δ V = V_{f} - V_{i} = 0$

Q. Two concentric spherical conducting shells of radii R and 2R carry charges Q and 2Q respectively. Change in electric potential on the outer shell when both are connected by a conducting wire is (k=4(πε)0​1​)

zero

2R3kQ​

RkQ​

R2kQ​

When two concentric shells are connected by a wire the whole charge on inner shell is transferred to the outer shell. Potential of the outer shell (V)i​=2RkQ​+2Rk(2Q)​ Vi​=2R3kQ​ (V)f​=2Rk(3Q)​ ∴ΔV=Vf​−Vi​=0

Q. Two concentric spherical conducting shells of radii $R$ and $2 R$ carry charges $Q$ and $2 Q$ respectively. Change in electric potential on the outer shell when both are connected by a conducting wire is $(k = \frac{1}{4 ( π ε ) _{0}})$

$\frac{3 kQ}{2 R}$

$\frac{kQ}{R}$

$\frac{2 kQ}{R}$

When two concentric shells are connected by a wire the whole charge on inner shell is transferred to the outer shell.
Potential of the outer shell
$(V)_{i} = \frac{kQ}{2 R} + \frac{k ( 2 Q )}{2 R}$
$V_{i} = \frac{3 kQ}{2 R}$
$(V)_{f} = \frac{k ( 3 Q )}{2 R}$
$∴ Δ V = V_{f} - V_{i} = 0$