Two concentric and coplanar circular coils having radius r1 and r2 are shown in figure. The resistance of inner coil is R. If the current in outer coil is increased from 0 to I, then the total charge that passes in the inner coil is (r2 r1)

Question

Two concentric and coplanar circular coils having radius r1 and r2 are shown in figure. The resistance of inner coil is R. If the current in outer coil is increased from 0 to I, then the total charge that passes in the inner coil is (r2 >> r1) (A) (μoπ/r21/2Rr2) (B) (μoπ/r22/2Rr1) (C) (μo/r22/Rr1) (D) (μo/r21/Rr2)

Tardigrade Admin · Accepted Answer

dq = M((di/R)) dq = (μoπ r21/2r2)[(l-0/R)]

Q. Two concentric and coplanar circular coils having radius $r_{1}$ and $r_{2}$ are shown in figure. The resistance of inner coil is R. If the current in outer coil is increased from 0 to I, then the total charge that passes in the inner coil is $(r_{2} >> r_{1})$

$\frac{μ _{o} π / r _{1}^{2}}{2 R r _{2}}$

$\frac{μ _{o} π / r _{2}^{2}}{2 R r _{1}}$

$\frac{μ _{o} / r _{2}^{2}}{R r _{1}}$

$\frac{μ _{o} / r _{1}^{2}}{R r _{2}}$

$d q = M (\frac{d i}{R})$
$d q = \frac{μ _{o} π r _{1}^{2}}{2 r _{2}} [\frac{l - 0}{R}]$

Q. Two concentric and coplanar circular coils having radius r1​ and r2​ are shown in figure. The resistance of inner coil is R. If the current in outer coil is increased from 0 to I, then the total charge that passes in the inner coil is (r2​>>r1​)

2Rr2​μo​π/r12​​

2Rr1​μo​π/r22​​

Rr1​μo​/r22​​

Rr2​μo​/r12​​