Two coils of self inductance 1 H and 3H are connected in series to support each other. Their mutual inductance is 6H. What is the self inductance of the combination ?

Question

Two coils of self inductance 1 H and 3H are connected in series to support each other. Their mutual inductance is 6H. What is the self inductance of the combination ? (A) 10 H (B) 16 H (C) 26 H (D) 40 H

Tardigrade Admin · Accepted Answer

L = L1 + L2 + 2 M = 1 + 3 +2 × 6 = 16 H

Q. Two coils of self inductance 1 H and 3H are connected in series to support each other. Their mutual inductance is 6H. What is the self inductance of the combination ?

10 H

16 H

26 H

40 H

$L = L_{1} + L_{2} + 2 M$ = 1 + 3 +2 $\times$ 6 = 16 H

Q. Two coils of self inductance 1 H and 3H are connected in series to support each other. Their mutual inductance is 6H. What is the self inductance of the combination ?

10 H

16 H

26 H

40 H

L=L1​+L2​+2M = 1 + 3 +2 × 6 = 16 H

$L = L_{1} + L_{2} + 2 M$ = 1 + 3 +2 $\times$ 6 = 16 H