Two coherent monochromatic light sources are located at two vertices of an equilateral triangle. If the intensity due to each of the sources independently is 1 Wm-2 ) at the third vertex, the resultant intensity due to both the sources at that point (i.e., at the third vertex) is: (in text Wn-2)

Question

Two coherent monochromatic light sources are located at two vertices of an equilateral triangle. If the intensity due to each of the sources independently is 1 Wm-2 ) at the third vertex, the resultant intensity due to both the sources at that point (i.e., at the third vertex) is: (in text Wn-2)  (A) Zero (B)  √2  (C) 2 (D) 4

Tardigrade Admin · Accepted Answer

I1=I2=1 Wm-2 So, resultant intensity at third vertex I=(√I1+√I2)2 =(√1+√1)2=(1+1)2=4 Wm-2

Zero

$2$

2

4

$I_{1} = I_{2} = 1 W m^{- 2}$ So, resultant intensity at third vertex $I = (I_{1} + I_{2})^{2}$ $= (1 + 1)^{2} = (1 + 1)^{2} = 4 W m^{- 2}$

Q. Two coherent monochromatic light sources are located at two vertices of an equilateral triangle. If the intensity due to each of the sources independently is 1 Wm-2 ) at the third vertex, the resultant intensity due to both the sources at that point (i.e., at the third vertex) is: (inWn−2)

Zero

2​

2

4

I1​=I2​=1Wm−2 So, resultant intensity at third vertex I=(I1​​+I2​​)2 =(1​+1​)2=(1+1)2=4Wm−2

$2$

$I_{1} = I_{2} = 1 W m^{- 2}$ So, resultant intensity at third vertex $I = (I_{1} + I_{2})^{2}$ $= (1 + 1)^{2} = (1 + 1)^{2} = 4 W m^{- 2}$