Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A=10 cm 2 and length =20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is (μ0=4 π ×-7 Tm A-1)

Question

Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A=10 cm 2 and length =20 cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is (μ0=4 π ×-7 Tm A-1) (A) 2.4 π ×10-5 H (B) 4.8 π ×10-4 H (C) 4.8 π ×10-5 H (D) 2.4 π ×10-4 H

Tardigrade Admin · Accepted Answer

M =(μ0 N 1 N 2 A /1) =(4 π × 10-7 × 300 × 400 × 10 × 10-4/0.2) =2.4 π × 10-4 H

Q. Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area $A = 10 c m^{2}$ and length $= 20 c m$ . If one of the solenoid has $300$ turns and the other $400$ turns, their mutual inductance is $(μ_{0} = 4 π \times^{- 7} T m A^{- 1})$

$2.4 π \times 1 0^{- 5} H$

$4.8 π \times 1 0^{- 4} H$

$4.8 π \times 1 0^{- 5} H$

$2.4 π \times 1 0^{- 4} H$

$M = \frac{μ _{0} N _{1} N _{2} A}{1}$
$= \frac{4 π \times 1 0 ^{- 7} \times 300 \times 400 \times 10 \times 1 0 ^{- 4}}{0.2}$
$= 2.4 π \times 1 0^{- 4} H$

Q. Two coaxial solenoids are made by winding thin insulated wire over a pipe of cross-sectional area A=10cm2 and length =20cm. If one of the solenoid has 300 turns and the other 400 turns, their mutual inductance is (μ0​=4π×−7TmA−1)

2.4π×10−5H

4.8π×10−4H

4.8π×10−5H

2.4π×10−4H