Two cars A and B are moving with same speed of 45 km/h along same direction. If a third car C coming from the opposite direction with a speed of 36 km/h meets two cars in an interval of 5 min , the distance of separation of two cars A and B should be (in km)

Question

Two cars A and B are moving with same speed of 45 km/h along same direction. If a third car C coming from the opposite direction with a speed of 36 km/h meets two cars in an interval of 5 min , the distance of separation of two cars A and B should be (in km) (A) 6.75 (B) 7.25 (C) 5.55 (D) 8.35

Tardigrade Admin · Accepted Answer

vrel=45+36=81 km/h=81× (5/18)m/s srel=vrel× t=81× (5/18)× (5× 60) =(81× 5× 5× 60/18)=6750m=6.75 km

Q. Two cars $A$ and $B$ are moving with same speed of $45 km / h$ along same direction. If a third car $C$ coming from the opposite direction with a speed of $36 km / h$ meets two cars in an interval of $5 min$ , the distance of separation of two cars $A$ and $B$ should be (in km)

6.75

7.25

5.55

8.35

4.75

$v_{re l} = 45 + 36 = 81 km / h = 81 \times \frac{5}{18} m / s$
$s_{re l} = v_{re l} \times t = 81 \times \frac{5}{18} \times (5 \times 60)$
$= \frac{81 \times 5 \times 5 \times 60}{18} = 6750 m = 6.75 km$

Q. Two cars A and B are moving with same speed of 45km/h along same direction. If a third car C coming from the opposite direction with a speed of 36km/h meets two cars in an interval of 5min , the distance of separation of two cars A and B should be (in km)