Two capacitors of capacities 2 C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors will now be:

Question

Two capacitors of capacities 2 C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors will now be: (A) (V/K+2) (B) (V/K) (C) (3 V/K+2) (D) (3 V/K)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/93336e18e803b018f126ba3f6fe72caf-.png" /> VC=(2 C V+C V/K C+2 C) =(3 V/K+2)

Q. Two capacitors of capacities $2 C$ and $C$ are joined in parallel and charged up to potential $V$ . The battery is removed and the capacitor of capacity $C$ is filled completely with a medium of dielectric constant $K$ . The potential difference across the capacitors will now be:

$\frac{V}{K + 2}$

$\frac{V}{K}$

$\frac{3 V}{K + 2}$

$\frac{3 V}{K}$

$V_{C} = \frac{2 C V + C V}{K C + 2 C}$
$= \frac{3 V}{K + 2}$

Q. Two capacitors of capacities 2C and C are joined in parallel and charged up to potential V. The battery is removed and the capacitor of capacity C is filled completely with a medium of dielectric constant K. The potential difference across the capacitors will now be:

K+2V​

KV​

K+23V​

K3V​