Two capacitors of capacitances C1 and C2 are connected in parallel across a battery. If Q1 and Q2 respectively be the charges on the capacitors, then Q1/Q2=

Question

Two capacitors of capacitances C1 and C2 are connected in parallel across a battery. If Q1 and Q2 respectively be the charges on the capacitors, then Q1/Q2= (A) (C2/C1) (B) (C1/C2) (C) (C12/C2) (D) (C22/C1)

Tardigrade Admin · Accepted Answer

Potential difference is same for both. That is Q1 /C1 = Q2/C2 Hence Q1 / Q2 = C1 /C2

Q. Two capacitors of capacitances $C_{1}$ and $C_{2}$ are connected in parallel across a battery. If $Q_{1}$ and $Q_{2}$ respectively be the charges on the capacitors, then $Q_{1} / Q_{2}$ =

$\frac{C _{2}}{C _{1}}$

$\frac{C _{1}}{C _{2}}$

$\frac{C _{1}^{2}}{C _{2}}$

$\frac{C _{2}^{2}}{C _{1}}$

Potential difference is same for both. That is $Q_{1} / C_{1} = Q_{2} / C_{2}$
Hence $Q_{1} / Q_{2} = C_{1} / C_{2}$

Q. Two capacitors of capacitances C1​ and C2​ are connected in parallel across a battery. If Q1​ and Q2​ respectively be the charges on the capacitors, then Q1​/Q2​=

C1​C2​​

C2​C1​​

C2​C12​​

C1​C22​​