Effective resistance in series is sum of individual resistances. Power consumed by a bulb, potential difference across which is V, is P=RV2
where, R is resultant resistance. In series combination, R=R1+R2 ∴P=R1+R2V2=P1V2+P2V2V2 ⇒P1=P11+P21 =2001+1001 ⇒P=67W