Question

Two buffer solutions, A and B each made with acetic acid and sodium acetate differ in their pH by one unit, A has salt: acid $=x:y$, B has salt : acid $=y:x$. If $x>y$, then the value of $x:y$ is

• A. 10,000
• B. $3.17$
• C. $6.61$
• D. $2.10$

Answer 1

Answer: (B)

Buffer (A):
$p{H}_1=p{K}_a+\log \left(\frac{x}{y}\right)\dots \text{ (i) }$
Buffer (B):
$p{H}_2=p{K}_a+\log \left(\frac{x}{y}\right)\dots \text{ (ii) }$
Since $x>y$
$\therefore p{H}_1-p{H}_2=1=\log \frac{x}{y}-\log \frac{y}{x}$
$\therefore 1=2\log \frac{x}{y}$
$\log \frac{x}{y}=\frac{1}{2}=0.5$
$\frac{x}{y}=\text{ Antilog }(0.5)=3.17$