Two bodies of masses m1 and m2 are connected by a light, inextensible string which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is

Question

Two bodies of masses m1 and m2 are connected by a light, inextensible string which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is (A) (4 m1 m2/m1+m2) g (B) (m1+m2/4 m1 m2) g (C) (m1 m2/m1+m2) g (D) (m1-m2/m1+m2) g

Tardigrade Admin · Accepted Answer

If pulley is accelerated upwards with a, then it becomes an AFR. Let a prime be the acceleration for m1 and m2 in AFR, then, T-m1 g-m1 a=m1 a prime (1) m2 g+m2 a-T=m2 a prime (2) Do (1) ÷(2) (T-m1(g+a)/m2(g+a)-T)=(m1/m2) ⇒ m2 T-m1 m2(g+a) =m1 m2(g+a)-m1 T or (m1+m2) T=2 m1 m2(g+a) T=(2 m1 m2(g+a)/m1+m2) Here a=g ⇒ T=(4 m1 m2 g/m1+m2) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/fbc86a0f1fa440c605c9284136a82ed0-.png" />

Q. Two bodies of masses $m_{1}$ and $m_{2}$ are connected by a light, inextensible string which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration $g,$ then the tension in the string is

$\frac{4 m _{1} m _{2}}{m _{1} + m _{2}} g$

$\frac{m _{1} + m _{2}}{4 m _{1} m _{2}} g$

$\frac{m _{1} m _{2}}{m _{1} + m _{2}} g$

$\frac{m _{1} - m _{2}}{m _{1} + m _{2}} g$

Q. Two bodies of masses m1​ and m2​ are connected by a light, inextensible string which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is

m1​+m2​4m1​m2​​g

4m1​m2​m1​+m2​​g

m1​+m2​m1​m2​​g

m1​+m2​m1​−m2​​g

Q. Two bodies of masses $m_{1}$ and $m_{2}$ are connected by a light, inextensible string which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration $g,$ then the tension in the string is

$\frac{4 m _{1} m _{2}}{m _{1} + m _{2}} g$

$\frac{m _{1} + m _{2}}{4 m _{1} m _{2}} g$

$\frac{m _{1} m _{2}}{m _{1} + m _{2}} g$

$\frac{m _{1} - m _{2}}{m _{1} + m _{2}} g$