Two bodies of masses 1 kg and 1 kg 2 kg are moving in two perpendicular direction with velocities 1 m / s and 2 m / s as shown in figure. The velocity of the centre of mass (in magnitude) of the be:

Question

Two bodies of masses 1 kg and 1 kg 2 kg are moving in two perpendicular direction with velocities 1 m / s and 2 m / s as shown in figure. The velocity of the centre of mass (in magnitude) of the be: (A) 3 m/s (B) 1.67 m/s (C) 1.5 m/s (D) 1.37 m/s

Tardigrade Admin · Accepted Answer

vecv cm =(1 × hati+2 × 2 hatj/1+2)=( hati+4 hatj/3) | vecv cm |=(1/3) √12+42 =(√17/3)=1.37 m / s

Q. Two bodies of masses $1 k g$ and $1 k g$ $2 k g$ are moving in two perpendicular direction with velocities $1 m / s$ and $2 m / s$ as shown in figure. The velocity of the centre of mass (in magnitude) of the be:

3 m/s

1.67 m/s

1.5 m/s

1.37 m/s

$v_{c m} = \frac{1 \times i ^ + 2 \times 2 j ^}{1 + 2} = \frac{i ^ + 4 j ^}{3}$
$∣ v_{c m} ∣ = \frac{1}{3} 1^{2} + 4^{2}$
$= \frac{17}{3} = 1.37 m / s$

Q. Two bodies of masses 1kg and 1kg 2kg are moving in two perpendicular direction with velocities 1m/s and 2m/s as shown in figure. The velocity of the centre of mass (in magnitude) of the be: