Q.
Two bodies of 6 kg and 4 kg masses have their velocity 5i^−2j^+10k^ and 10i^−2j^+5k^ respectively. Then the velocity of their centre of mass is
10655
215
System of Particles and Rotational Motion
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Solution:
Here, m1=6kg,m2=4kg υ1=5i^−2j^+10k^ υ2=10i^−2j^+5k^
The velocity of the centre of mass is υCM=m1+m2m1υ1+m2υ2 =6+4(6)(5i^−2j^+10k^)+4(10i^−2j^+5k^) =1030i^−12j^+60k^−8j^+20k^ =1070i^−20j^+80k^=7i^−2j^+8k^