Two blocks of masses m and M are connected by means of a metal wire of cross-sectional area A passing over a frictionless fixed pulley as shown in the figure. The system is then released. If M = 2 m, then the stress produced in the wire is:

Question

Two blocks of masses m and M are connected by means of a metal wire of cross-sectional area A passing over a frictionless fixed pulley as shown in the figure. The system is then released. If M = 2 m, then the stress produced in the wire is: (A) (2 m g/3 A) (B) (4 m g/3 A) (C) (m g/A) (D) (3 mg/4 A)

Tardigrade Admin · Accepted Answer

Tension in the wire, T ≈ ((2 m M/m+M)) g Stress =(Force/Tension /Area)=(2 m M/A (m+M)) g =(2(m ×2m)/A (m+2 m)) (M = 2mgiven) =(4 m2/3 m A) g =(4 m g/3 A)

Q. Two blocks of masses $m$ and $M$ are connected by means of a metal wire of cross-sectional area $A$ passing over a frictionless fixed pulley as shown in the figure. The system is then released. If $M = 2 m$ , then the stress produced in the wire is:

$\frac{2 m g}{3 A}$

$\frac{4 m g}{3 A}$

$\frac{m g}{A}$

$\frac{3 m g}{4 A}$

Tension in the wire, $T \approx (\frac{2 m M}{m + M}) g$
Stress = $\frac{F orce / T e n s i o n}{A re a} = \frac{2 m M}{A ( m + M )} g$
$= \frac{2 ( m \times 2 m )}{A ( m + 2 m )}$ (M = 2mgiven)
$= \frac{4 m ^{2}}{3 m A} g = \frac{4 m g}{3 A}$

Q. Two blocks of masses m and M are connected by means of a metal wire of cross-sectional area A passing over a frictionless fixed pulley as shown in the figure. The system is then released. If M=2m, then the stress produced in the wire is:

3A2mg​

3A4mg​

Amg​

4A3mg​