Two blocks of masses m1=4 kg and m2=2 kg are connected to the ends of a string which passes over a massless, frictionless pulley. The total downwards thrust on the pulley is nearly

Question

Two blocks of masses m1=4 kg and m2=2 kg are connected to the ends of a string which passes over a massless, frictionless pulley. The total downwards thrust on the pulley is nearly <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-fd5vcupojuldipm1.jpg" /> (A) 27N (B) 54 N (C) 0.8 N (D) Zero

Tardigrade Admin · Accepted Answer

T=(2 m1 m2/m1 + m2)g=(2 × 4 × 2 × 10/4 + 2) =(160/6)=26.6=27 N Total downward thrust on the pulley =2T=2× 27=54 N

Q. Two blocks of masses $m_{1} = 4$ kg and $m_{2} = 2$ kg are connected to the ends of a string which passes over a massless, frictionless pulley. The total downwards thrust on the pulley is nearly

$27 N$

$54 N$

$0.8 N$

Zero

$T = \frac{2 m _{1} m _{2}}{m _{1} + m _{2}} g = \frac{2 \times 4 \times 2 \times 10}{4 + 2}$
$= \frac{160}{6} = 26.6 = 27 N$
Total downward thrust on the pulley
$= 2 T = 2 \times 27 = 54$ N

Q. Two blocks of masses m1​=4 kg and m2​=2 kg are connected to the ends of a string which passes over a massless, frictionless pulley. The total downwards thrust on the pulley is nearly

27N

54N

0.8N