Two blocks of masses 7 kg and 5 kg are connected by a rope of mass 4 kg. The system is pulled up with a force of 240 N as shown in figure. The tension in the rope at its midpoint A is

Question

Two blocks of masses 7 kg and 5 kg are connected by a rope of mass 4 kg. The system is pulled up with a force of 240 N as shown in figure. The tension in the rope at its midpoint A is (A) 105 N (B) 270 N (C) 240 N (D) 50 N

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/9021eb214132a29a224f43775f1c458d-.png" /> The common acceleration of the system is a=(240/(7+4+5))=15 m s-2 The tension in the rope at its midpoint A is TA=(2+5)a=7a=7×15 =105 N

Q. Two blocks of masses $7 k g$ and $5 k g$ are connected by a rope of mass $4 k g$ . The system is pulled up with a force of $240 N$ as shown in figure. The tension in the rope at its midpoint $A$ is

$105 N$

$270 N$

$240 N$

$50 N$

The common acceleration of the system is
$a = \frac{240}{( 7 + 4 + 5 )} = 15 m s^{- 2}$
The tension in the rope at its midpoint $A$ is
$T_{A} = (2 + 5) a = 7 a = 7 \times 15$
$= 105 N$

Q. Two blocks of masses 7kg and 5kg are connected by a rope of mass 4kg. The system is pulled up with a force of 240N as shown in figure. The tension in the rope at its midpoint A is

105N

270N

240N

50N