Two blocks of masses 40 kg and 20 kg are connected by a wire that has a linear mass density of 1 g / m. These blocks are being pulled across horizontal frictionless floor by horizontal force F that is applied to 20 kg block. A transverse wave travels on the wave between the blocks with a speed of 400 m / s (relative to the wire). The mass of the wire is negligible compared to the mass of the blocks. The magnitude of F is

Question

Two blocks of masses 40 kg and 20 kg are connected by a wire that has a linear mass density of 1 g / m. These blocks are being pulled across horizontal frictionless floor by horizontal force F that is applied to 20 kg block. A transverse wave travels on the wave between the blocks with a speed of 400 m / s (relative to the wire). The mass of the wire is negligible compared to the mass of the blocks. The magnitude of F is (A) 160 N (B) 240 N (C) 320 N (D) 400 N

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/f31fc9b2e318e618d6a860504ce4cf5e-.png" /> Tension T in the wire =v2 ρ =(400)2 × 10-3=160 N Force applied F=(T(m1+m2)/m1) =160 × ((40+20)/40)=240 N

$160 N$

$240 N$

$320 N$

$400 N$

Tension $T$ in the wire $= v^{2} ρ$
$= (400)^{2} \times 1 0^{- 3} = 160 N$
Force applied $F = \frac{T ( m _{1} + m _{2} )}{m _{1}}$
$= 160 \times \frac{( 40 + 20 )}{40} = 240 N$

160N

240N

320N

400N

Tension T in the wire =v2ρ =(400)2×10−3=160N Force applied F=m1​T(m1​+m2​)​ =160×40(40+20)​=240N

$160 N$

$240 N$

$320 N$

$400 N$

Tension $T$ in the wire $= v^{2} ρ$
$= (400)^{2} \times 1 0^{- 3} = 160 N$
Force applied $F = \frac{T ( m _{1} + m _{2} )}{m _{1}}$
$= 160 \times \frac{( 40 + 20 )}{40} = 240 N$