Two blocks of masses 2m and 3m are connected through a string which passes over a pulley (disc) of mass m and radius R as shown in figure. If system is released from rest and string does not slip on the pulley, then angular acceleration of the pulley is

Question

Two blocks of masses 2m and 3m are connected through a string which passes over a pulley (disc) of mass m and radius R as shown in figure. If system is released from rest and string does not slip on the pulley, then angular acceleration of the pulley is (A) (2g/7R) (B) (4g/11R) (C) (g/3R) (D) (g/2R)

Tardigrade Admin · Accepted Answer

2mg - T1 = 2 m × a... (i) T2 = 3 m× a...(ii) (T1-T2)R= I×α...(iii) 2mg = (5× m × R+(1/2)mR)α α=(4g/11R)

Q. Two blocks of masses $2 m$ and $3 m$ are connected through a string which passes over a pulley (disc) of mass $m$ and radius $R$ as shown in figure. If system is released from rest and string does not slip on the pulley, then angular acceleration of the pulley is

$\frac{2 g}{7 R}$

$\frac{4 g}{11 R}$

$\frac{g}{3 R}$

$\frac{g}{2 R}$

$2 m g - T_{1} = 2 m \times a$ ... (i)
$T_{2} = 3 m \times a$ ...(ii)
$(T_{1} - T_{2}) R = I \times α$ ...(iii)
$2 m g = (5 \times m \times R + \frac{1}{2} m R) α$
$α = \frac{4 g}{11 R}$

Q. Two blocks of masses 2m and 3m are connected through a string which passes over a pulley (disc) of mass m and radius R as shown in figure. If system is released from rest and string does not slip on the pulley, then angular acceleration of the pulley is

7R2g​

11R4g​

3Rg​

2Rg​