Two blocks of masses 10 kg and 30 kg are placed on the same straight line with coordinates (0,0) cm and ( x , 0) cm respectively. The block of 10 kg is moved on the same line through a distance of 6 cm towards the other block. The distance through which the block of 30 kg must be moved to keep the position of centre of mass of the system unchanged is :

Question

Two blocks of masses 10 kg and 30 kg are placed on the same straight line with coordinates (0,0) cm and ( x , 0) cm respectively. The block of 10 kg is moved on the same line through a distance of 6 cm towards the other block. The distance through which the block of 30 kg must be moved to keep the position of centre of mass of the system unchanged is : (A) 4 cm towards the 10 kg block (B) 2 cm away from the 10 kg block (C) 2 cm towards the 10 kg block (D) 4 cm away from the 10 kg block

Tardigrade Admin · Accepted Answer

Δ xG=(m1 Δ x1+m2 Δ x2/m1+m2) 0=(10 × 6+30(Δ x2)/40) Δ x2=-2 cm Block of mass 30 kg will to move towards 10 kg.

$4 c m$ towards the $10 k g$ block

$2 c m$ away from the $10 k g$ block

$2 c m$ towards the $10 k g$ block

$4 c m$ away from the $10 k g$ block

$Δ x_{G} = \frac{m _{1} Δ x _{1} + m _{2} Δ x _{2}}{m _{1} + m _{2}}$
$0 = \frac{10 \times 6 + 30 ( Δ x _{2} )}{40}$
$Δ x_{2} = - 2 c m$
Block of mass $30 k g$ will to move towards $10 k g$ .

4cm towards the 10kg block

2cm away from the 10kg block

2cm towards the 10kg block

4cm away from the 10kg block

ΔxG​=m1​+m2​m1​Δx1​+m2​Δx2​​ 0=4010×6+30(Δx2​)​ Δx2​=−2cm Block of mass 30kg will to move towards 10kg.

$4 c m$ towards the $10 k g$ block

$2 c m$ away from the $10 k g$ block

$2 c m$ towards the $10 k g$ block

$4 c m$ away from the $10 k g$ block

$Δ x_{G} = \frac{m _{1} Δ x _{1} + m _{2} Δ x _{2}}{m _{1} + m _{2}}$
$0 = \frac{10 \times 6 + 30 ( Δ x _{2} )}{40}$
$Δ x_{2} = - 2 c m$
Block of mass $30 k g$ will to move towards $10 k g$ .