Two blocks of mass m and M are connected by a massless thread which passes over a fixed massless pulley. The table under M is smooth. The force exerted by the pulley on the table is

Question

Two blocks of mass m and M are connected by a massless thread which passes over a fixed massless pulley. The table under M is smooth. The force exerted by the pulley on the table is <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-vpn8iz4kaypb.png" /> (A) (√2 M m g/M + m) (B) (M m g/M + m) (C) (2 M m g/M + m) (D) (√3 M m g/M + m)

Tardigrade Admin · Accepted Answer

(m + M)a=mg a=(m g/M + m) T=(M m g/M + m) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-vpn8iz4krorx.png" /> N=T√2=(M m g √2/M + m)

Q. Two blocks of mass $m$ and $M$ are connected by a massless thread which passes over a fixed massless pulley. The table under $M$ is smooth. The force exerted by the pulley on the table is

$\frac{2 M m g}{M + m}$

$\frac{M m g}{M + m}$

$\frac{2 M m g}{M + m}$

$\frac{3 M m g}{M + m}$

$(m + M) a = m g$
$a = \frac{m g}{M + m}$
$T = \frac{M m g}{M + m}$

$N = T 2 = \frac{M m g 2}{M + m}$

Q. Two blocks of mass m and M are connected by a massless thread which passes over a fixed massless pulley. The table under M is smooth. The force exerted by the pulley on the table is

M+m2​Mmg​

M+mMmg​

M+m2Mmg​

M+m3​Mmg​

(m+M)a=mg a=M+mmg​ T=M+mMmg​ N=T2​=M+mMmg2​​

Q. Two blocks of mass $m$ and $M$ are connected by a massless thread which passes over a fixed massless pulley. The table under $M$ is smooth. The force exerted by the pulley on the table is

$\frac{2 M m g}{M + m}$

$\frac{M m g}{M + m}$

$\frac{2 M m g}{M + m}$

$\frac{3 M m g}{M + m}$

$(m + M) a = m g$
$a = \frac{m g}{M + m}$
$T = \frac{M m g}{M + m}$

$N = T 2 = \frac{M m g 2}{M + m}$