Two blocks of mass M1 = 20 kg and M2 = 12 kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is :

Question

Two blocks of mass M1 = 20 kg and M2 = 12 kg are connected by a metal rod of mass 8 kg. The system is pulled vertically up by applying a force of 480 N as shown. The tension at the mid-point of the rod is : (A) 144 N (B) 96 N (C) 240 N (D) 192 N

Tardigrade Admin · Accepted Answer

Acceleration produced in upward direction a=(F/M1+M2+Mass of metal rod) =(480/20+12+8)=12 ms-2 Tension at the mid point T=(M2+(Mass of rod/2))a = (12 + 4) x 12= 192 N

Q. Two blocks of mass $M_{1} = 20 k g$ and $M_{2} = 12 k g$ are connected by a metal rod of mass $8 k g$ . The system is pulled vertically up by applying a force of $480 N$ as shown. The tension at the mid-point of the rod is :

$144 N$

$96 N$

$240 N$

$192 N$

Acceleration produced in upward direction
$a = \frac{F}{M _{1} + M _{2} + M a ss o f m e t a l ro d}$
$= \frac{480}{20 + 12 + 8} = 12 m s^{- 2}$
Tension at the mid point
$T = (M_{2} + \frac{M a ss o f ro d}{2}) a$
$= (12 + 4) x 12 = 192 N$

Q. Two blocks of mass M1​=20kg and M2​=12kg are connected by a metal rod of mass 8kg. The system is pulled vertically up by applying a force of 480N as shown. The tension at the mid-point of the rod is :

144N

96N

240N

192N