Two blocks of mass 1 kg 2 kg are hanged from a light pulley and resting on a horizontal surface. A time varying force F = 4t N is acting on pulley in the direction shown. Time after which block will break off the surface will be -

Question

Two blocks of mass 1 kg 2 kg are hanged from a light pulley and resting on a horizontal surface. A time varying force F = 4t N is acting on pulley in the direction shown. Time after which block will break off the surface will be - <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-uuykz2tk2bc4.png" /> (A) 5 (B) 10 (C) 15 (D) 20

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-uuykz2tkydtj.png" /> 1 kg block N+F/2=10; ⇒ F=2(.10-N.) Block 1 will leave surface when N = 0 ⇒ F=20⇒ 5sec

Q. Two blocks of mass 1 kg & 2 kg are hanged from a light pulley and resting on a horizontal surface. A time varying force F = 4t N is acting on pulley in the direction shown. Time after which block will break off the surface will be -

5

10

15

20

1 kg block
$N + F /2 = 10;$
$\Rightarrow F = 2 (10 - N)$
Block 1 will leave
surface when N = 0
$\Rightarrow F = 20 \Rightarrow 5 sec$

Q. Two blocks of mass 1 kg & 2 kg are hanged from a light pulley and resting on a horizontal surface. A time varying force F = 4t N is acting on pulley in the direction shown. Time after which block will break off the surface will be -

5

10

15

20

1 kg block N+F/2=10; ⇒F=2(10−N) Block 1 will leave surface when N = 0 ⇒F=20⇒5sec

1 kg block
$N + F /2 = 10;$
$\Rightarrow F = 2 (10 - N)$
Block 1 will leave
surface when N = 0
$\Rightarrow F = 20 \Rightarrow 5 sec$