Question

Two blocks $(m=0.5kg$ and $M=4.5kg)$ are arranged on a horizontal frictionless table as shown in figure. The coefficient of static friction between the two blocks is $\frac{3}{7}$. Then the maximum horizontal force that can be applied on the larger block so that the blocks move together is _________ $N$. (Round off to the Nearest Integer) [Take g as $9.8m{s}^{-2}$ ]

Answer 1

Answer: 21

$a_{\max }=\mu g=\frac{3}{7}\times 9.8$
$F=(M+m)a_{\max }=5a_{\max }$
$=21$ Newton