Two blocks, each having a mass M, rest on frictionless surface as shown in the figure. If the pulleys are light and frictionless, and M on the incline is allowed to move down, then the tension in the string will be :-

Question

Two blocks, each having a mass M, rest on frictionless surface as shown in the figure. If the pulleys are light and frictionless, and M on the incline is allowed to move down, then the tension in the string will be :- (A) 2.3 Mg sin θ (B) 1.3 Mg sin θ (C) ( Mg /2) sin θ (D) 2 Mg sin 0

Tardigrade Admin · Accepted Answer

a=(M g sin θ/(M+M))=(g/2) sin θ ∴ T=M a=(M g/2) sin θ

Q. Two blocks, each having a mass $M$ , rest on frictionless surface as shown in the figure. If the pulleys are light and frictionless, and $M$ on the incline is allowed to move down, then the tension in the string will be :-

$2.3 M g sin θ$

$1.3 M g sin θ$

$\frac{M g}{2} sin θ$

$2 M g sin 0$

$a = \frac{M g s i n θ}{( M + M )} = \frac{g}{2} sin θ$
$∴ T = M a = \frac{M g}{2} sin θ$

Q. Two blocks, each having a mass M, rest on frictionless surface as shown in the figure. If the pulleys are light and frictionless, and M on the incline is allowed to move down, then the tension in the string will be :-

2.3Mgsinθ

1.3Mgsinθ

2Mg​sinθ

2Mgsin0