Two blocks are in contact on a frictionless table. One has mass m and other 2 m . A force F is applied on 2 m as shown in figure. Next the same force F is applied from the right on m . In the two cases respectively, the ratio of the force of contact between the two blocks will be

Question

Two blocks are in contact on a frictionless table. One has mass m and other 2 m . A force F is applied on 2 m as shown in figure. Next the same force F is applied from the right on m . In the two cases respectively, the ratio of the force of contact between the two blocks will be <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-hslstnalui2v.png" /> (A) 2: 1 (B) 1: 3 (C) 1: 2 (D) 3: 1

Tardigrade Admin · Accepted Answer

When force F is applied on 2 m from left, contact force, F1=(m/m + 2 m)F=(F/3) When force F is applied on m from right, contact force F2=(2 m/m + 2 m)F=(2 F/3) ∴ F1:F2=1:2

Q. Two blocks are in contact on a frictionless table. One has mass $m$ and other 2 $m$ . A force $F$ is applied on 2 $m$ as shown in figure. Next the same force $F$ is applied from the right on $m$ . In the two cases respectively, the ratio of the force of contact between the two blocks will be

2 : 1

1 : 3

1 : 2

3 : 1

When force $F$ is applied on $2 m$ from left, contact force,
$F_{1} = \frac{m}{m + 2 m} F = \frac{F}{3}$
When force $F$ is applied on $m$ from right, contact force
$F_{2} = \frac{2 m}{m + 2 m} F = \frac{2 F}{3}$
$∴ F_{1} : F_{2} = 1 : 2$

Q. Two blocks are in contact on a frictionless table. One has mass m and other 2 m . A force F is applied on 2 m as shown in figure. Next the same force F is applied from the right on m . In the two cases respectively, the ratio of the force of contact between the two blocks will be