Q.
Two billiard balls A and B, each of mass 50g and moving in opposite directions with speed of 5ms−1 each, collide and rebound with the same speed. The impulse imparted to each ball is
Initial momentum of ball A=(0.05kg)(5ms−1) =0.25kgms−1
As the speed is reversed on collision,
Final momentum of the ball A=(0.05kg)(−5ms−1) =−0.25kgms−1
Impulse imparted to the ball A
= Change in momentum of ball A
= Final momentum - Initial momentum =−0.25kgms−1−0.25kgms−1=−0.5kgms−1
Similarly,
Initial momentum of ball B=(0.05kg)(−5ms−1) =−0.25kgms−1
Final momentum of ball B=(0.05kg)(5ms−1) =+0.25kgms−1
Impulse imparted to ball B=(0.25kgms−1) −(−0.25kgms−1) =0.5kgms−1
Impulse imparted to each ball is 0.5kgms−1 in magnitude. The two impulses are opposite in direction.