Two 220V,100W bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220V AC supply line. The power drawn by the combination in each case, respectively, will be

Question

Two 220V,100W bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220V AC supply line. The power drawn by the combination in each case, respectively, will be (A) 200W,150W (B) 50W,200W (C) 50W,100W (D) 100W,50W

Tardigrade Admin · Accepted Answer

When bulbs are connected in series with rated power

P_{1}

and

P_{2}

then total power consumption

P_{S} = \frac{P _{1} P _{2}}{P _{1} + P _{2}}

If bulbs are connected in parallel

P_{P} = P_{1} + P_{2}

so.

P_{S} = \frac{( 100 ) ( 100 )}{100 + 100} = 50 W

P_{P} = 100 + 100 = 200 W

Q. Two $220 V, 100 W$ bulbs are connected first in series and then in parallel. Each time the combination is connected to a $220 V$ AC supply line. The power drawn by the combination in each case, respectively, will be

$200 W, 150 W$

$50 W, 200 W$

$50 W, 100 W$

$100 W, 50 W$

When bulbs are connected in series with rated power $P_{1}$ and $P_{2}$ then total power consumption
$P_{S} = \frac{P _{1} P _{2}}{P _{1} + P _{2}}$
If bulbs are connected in parallel
$P_{P} = P_{1} + P_{2}$
so. $P_{S} = \frac{( 100 ) ( 100 )}{100 + 100} = 50 W$
$P_{P} = 100 + 100 = 200 W$

Q. Two 220V,100W bulbs are connected first in series and then in parallel. Each time the combination is connected to a 220V AC supply line. The power drawn by the combination in each case, respectively, will be

200W,150W

50W,200W

50W,100W

100W,50W