Question

Twelve resistors each of resistance $16\Omega$ are connected in the circuit as shown. The net resistance between $A$ and $B$ is

• A. $1\Omega$
• B. $2\Omega$
• C. $3\Omega$
• D. $4\Omega$

Answer 1

Answer: (D)

The equivalent circuit is shown in figure.
The equivalent resistance of each parallel branch is
$R_P=R\Vert R\Vert R=(1/R+1/R+$ $1/R{)}^{-1}=R/3$
Thus, net resistance is
$R_{\text{net }}=(R/3+R/3+R/3)\Vert (R/3)=R\Vert (R/3)$
$=\frac{R\times R/3}{R+R/3}=R/4=16/4=$
$4\Omega$