Question

Twelve resistors each of resistance $1\Omega$ are connected as shown in the figure. Net resistance between points $A$ and $H$ would be

• A. $\frac{5}{6}\Omega$
• B. $1\Omega$
• C. $\frac{3}{4}\Omega$
• D. $\frac{7}{12}\Omega$

Answer 1

Answer: (C)

Let current i enters from point A and leaves at H. Then current can be distributed as follows :



from the above diagram we can see that no current will flow in wires CE and FD. So, the simple circuit is as follows:



$\therefore {\text{R}}_{\text{AH}}=\frac{3}{4}\Omega$