Triangle ABC has vertices (0, 0), (11, 60) and (91, 0). If the line y=kx cuts the triangle into 2 two triangles of equal area, then k is equal to

Question

Triangle ABC has vertices (0, 0), (11, 60) and (91, 0). If the line y=kx cuts the triangle into 2 two triangles of equal area, then k is equal to (A)  (30/51)  (B)  (4/7)  (C)  (7/4)  (D)  (30/91)

Tardigrade Admin · Accepted Answer

As the line divides the Δ ABC in equal area. Midpoint of AB(51, 30) which lies on y=kx ∴ 30=51k⇒ k=(30/51)

Q. Triangle $A BC$ has vertices $(0, 0), (11, 60)$ and $(91, 0)$ . If the line $y = k x$ cuts the triangle into $2$ two triangles of equal area, then $k$ is equal to

$\frac{30}{51}$

$\frac{4}{7}$

$\frac{7}{4}$

$\frac{30}{91}$

$\frac{27}{37}$

As the line divides the $Δ A BC$ in equal area. Midpoint of AB(51, 30) which lies on
$y = k x$
$∴$ $30 = 51 k \Rightarrow k = \frac{30}{51}$

Q. Triangle ABC has vertices (0,0),(11,60) and (91,0). If the line y=kx cuts the triangle into 2 two triangles of equal area, then k is equal to

5130​

74​

47​

9130​

3727​

As the line divides the ΔABC in equal area. Midpoint of AB(51, 30) which lies on y=kx ∴ 30=51k⇒k=5130​