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  4. Triangle ABC has vertices (0, 0), (11, 60) and (91, 0). If the line y=kx cuts the triangle into 2 two triangles of equal area, then k is equal to

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Q. Triangle $ABC$ has vertices $(0, 0), (11, 60)$ and $(91, 0)$. If the line $ y=kx $ cuts the triangle into $2$ two triangles of equal area, then $k$ is equal to

KEAMKEAM 2009Straight Lines

Solution:

As the line divides the $ \Delta ABC $ in equal area. Midpoint of AB(51, 30) which lies on
$ y=kx $
$ \therefore $ $ 30=51k\Rightarrow k=\frac{30}{51} $

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