Treatment of ammonia with excess of ethyl chloride will yield

Question

Treatment of ammonia with excess of ethyl chloride will yield (A) Diethyl amine (B) Ethane (C) Tetraethyl ammonium chloride (D) Methyl amine

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/1c986e4a33b7974b6b7b492e2336f75f-.jpeg" /> If NH3 is in excess, then 1° amine will be the main product, if C2H5Cl is in excess then mixture of 1°, 2°, 3° and quaternary amine is obtained.

Q. Treatment of ammonia with excess of ethyl chloride will yield

Diethyl amine

Ethane

Tetraethyl ammonium chloride

Methyl amine

If $N H_{3}$ is in excess, then 1° amine will be the main product, if $C_{2} H_{5} Cl$ is in excess then mixture of $1°, 2°, 3°$ and quaternary amine is obtained.

Q. Treatment of ammonia with excess of ethyl chloride will yield

Diethyl amine

Ethane

Tetraethyl ammonium chloride

Methyl amine

If NH3​ is in excess, then 1° amine will be the main product, if C2​H5​Cl is in excess then mixture of 1°,2°,3° and quaternary amine is obtained.

If $N H_{3}$ is in excess, then 1° amine will be the main product, if $C_{2} H_{5} Cl$ is in excess then mixture of $1°, 2°, 3°$ and quaternary amine is obtained.