Total number of products form including stereoisomers during monochlorination of 2-methyl butane?

Question

Total number of products form including stereoisomers during monochlorination of 2-methyl butane? (A) 2 (B) 6 (C) 7 (D) 8

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/c-cwietenewgw4gyf1.jpg" /> The product I and III have one chiral centre, hence they give (2n. =21=2 ) two optical isomers as products. Totalproducts =2+1+2+1=6

Q. Total number of products form including stereoisomers during monochlorination of 2-methyl butane?

2

6

7

8

The product I and III have one chiral centre, hence they give $(2^{n}$ $= 2^{1} = 2$ ) two optical isomers as products.
Totalproducts $= 2 + 1 + 2 + 1 = 6$

Q. Total number of products form including stereoisomers during monochlorination of 2-methyl butane?

2

6

7

8

The product I and III have one chiral centre, hence they give (2n =21=2 ) two optical isomers as products. Totalproducts =2+1+2+1=6

The product I and III have one chiral centre, hence they give $(2^{n}$ $= 2^{1} = 2$ ) two optical isomers as products.
Totalproducts $= 2 + 1 + 2 + 1 = 6$