Q.
Total number of points of non-differentiability of f(x)=min{1,1+x3,x2−3x+3} is
1811
227
Continuity and Differentiability
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Solution:
y=x2−3x+3 and y=1,
when x2−3x+3=1 or x2−3x+2 =0 or x=1,2 y=x3+1 touches y=1 at x=0.
Further y=x3+1 and y=x2−3x+3 intersect at only one point.
From the graph f(x)=min{1,1+x3,x2−3x+3} is non-differentiable at x=1 and x=2