Torricelli’s barometer used mercury but Pascal duplicated it using French wine of density 984 kg m-3 . In that case, the height of the wine column for normal atmospheric pressure is (Take the density of mercury = 13.6 × 103 kg m-3 )

Question

Torricelli’s barometer used mercury but Pascal duplicated it using French wine of density 984 kg m-3 . In that case, the height of the wine column for normal atmospheric pressure is (Take the density of mercury = 13.6 × 103 kg m-3 ) (A)  5.5 m  (B)  10.5 m  (C)  9.8 m  (D)  15 m

Tardigrade Admin · Accepted Answer

As P =h ρ g Height of mercury column in Torricelli âs barometer =0.76 m of Hg, ρ textmercury=13.6 ×103 kg m-3 , ρ textfrench wine=984 kg m-3 or 0.76×(13.6×103)×9.8=h ×984 ×9.8 or h=(0.76×13.6×103×9.8/984×9.8) =10.5 m

Q. Torricelli’s barometer used mercury but Pascal duplicated it using French wine of density $984 k g m^{- 3}$ . In that case, the height of the wine column for normal atmospheric pressure is (Take the density of mercury $= 13.6 \times 1 0^{3} k g m^{- 3}$ )

$5.5 m$

$10.5 m$

$9.8 m$

$15 m$

Q. Torricelli’s barometer used mercury but Pascal duplicated it using French wine of density 984kgm−3 . In that case, the height of the wine column for normal atmospheric pressure is (Take the density of mercury =13.6×103kgm−3 )

5.5m

10.5m

9.8m

15m

As P=hρg Height of mercury column in Torricelli ’s barometer =0.76m of Hg, ρmercury​=13.6×103kgm−3 , ρfrench wine​=984kgm−3 or 0.76×(13.6×103)×9.8=h×984×9.8 or h=984×9.80.76×13.6×103×9.8​ =10.5m

Q. Torricelli’s barometer used mercury but Pascal duplicated it using French wine of density $984 k g m^{- 3}$ . In that case, the height of the wine column for normal atmospheric pressure is (Take the density of mercury $= 13.6 \times 1 0^{3} k g m^{- 3}$ )

$5.5 m$

$10.5 m$

$9.8 m$

$15 m$