Toluene reacts with bromine in the presence of the light to give benzyl bromide, while in presence of FeBr3 it gives p-bromotoluene. Give explanation for the above observation.

Question

Toluene reacts with bromine in the presence of the light to give benzyl bromide, while in presence of FeBr3 it gives p-bromotoluene. Give explanation for the above observation. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

In presence of light, free radical reaction takes place at -CH3 group while in presence of FeBr3, electrophilic substitution occur in the ring.

Q. Toluene reacts with bromine in the presence of the light to give benzyl bromide, while in presence of $F e B r_{3}$ it gives p-bromotoluene. Give explanation for the above observation.

In presence of light, free radical reaction takes place at $- C H_{3}$ group while in presence of FeBr3, electrophilic substitution occur in the ring.

Q. Toluene reacts with bromine in the presence of the light to give benzyl bromide, while in presence of FeBr3​ it gives p-bromotoluene. Give explanation for the above observation.

In presence of light, free radical reaction takes place at −CH3​ group while in presence of FeBr3, electrophilic substitution occur in the ring.

Q. Toluene reacts with bromine in the presence of the light to give benzyl bromide, while in presence of $F e B r_{3}$ it gives p-bromotoluene. Give explanation for the above observation.

In presence of light, free radical reaction takes place at $- C H_{3}$ group while in presence of FeBr3, electrophilic substitution occur in the ring.