To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorus acid (H3PO3), the volume of 0.1 M aqueous KOH solution required is

Question

To neutralize completely 20 mL of 0.1 M aqueous solution of phosphorus acid (H3PO3), the volume of 0.1 M aqueous KOH solution required is (A) 20 mL (B) 30 mL (C) 40 mL (D) 50 mL

Tardigrade Admin · Accepted Answer

H3PO3 is a dibasic acid. N1V1(acid)=N2V2(base) 0.1× 2× 20=0.1× 1× V2 V2=(0.1× 2× 20/0.1× 1) =40 mL

Q. To neutralize completely $20 m L$ of $0.1 M$ aqueous solution of phosphorus acid $(H_{3} P O_{3}),$ the volume of 0.1 M aqueous KOH solution required is

20 mL

30 mL

40 mL

50 mL

$H_{3} P O_{3}$ is a dibasic acid.
$N_{1} V_{1} (a c i d) = N_{2} V_{2} (ba se)$
$0.1 \times 2 \times 20 = 0.1 \times 1 \times V_{2}$
$V_{2} = \frac{0.1 \times 2 \times 20}{0.1 \times 1}$
$= 40 m L$

Q. To neutralize completely 20mL of 0.1M aqueous solution of phosphorus acid (H3​PO3​), the volume of 0.1 M aqueous KOH solution required is